Metamath Proof Explorer


Theorem sseq0b

Description: The only subclass of the empty class is itself. (Contributed by NM, 7-Mar-2007) Strengthen sseq0 to a biconditional. (Revised by BJ, 19-Jul-2026)

Ref Expression
Assertion sseq0b ⊢ A = ∅ → B ⊆ A ↔ B = ∅

Proof

Step Hyp Ref Expression
1 sseq2 ⊢ A = ∅ → B ⊆ A ↔ B ⊆ ∅
2 ss0b ⊢ B ⊆ ∅ ↔ B = ∅
3 1 2 bitrdi ⊢ A = ∅ → B ⊆ A ↔ B = ∅