Metamath Proof Explorer


Theorem ssexg

Description: The subset of a set is also a set. Exercise 3 of TakeutiZaring p. 22 (generalized). (Contributed by NM, 14-Aug-1994)

Ref Expression
Assertion ssexg A B B C A V

Proof

Step Hyp Ref Expression
1 sseq2 x = B A x A B
2 1 imbi1d x = B A x A V A B A V
3 vex x V
4 3 ssex A x A V
5 2 4 vtoclg B C A B A V
6 5 impcom A B B C A V