Metamath Proof Explorer


Theorem sspwimpcf

Description: If a class is a subclass of another class, then its power class is a subclass of that other class's power class. Left-to-right implication of Exercise 18 of TakeutiZaring p. 18. sspwimpcf , using conventional notation, was translated from its virtual deduction form, sspwimpcfVD , using a translation program. (Contributed by Alan Sare, 13-Jun-2015) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion sspwimpcf ⊢ A ⊆ B → 𝒫 A ⊆ 𝒫 B

Proof

Step Hyp Ref Expression
1 vex ⊢ x ∈ V
2 id ⊢ A ⊆ B → A ⊆ B
3 id ⊢ x ∈ 𝒫 A → x ∈ 𝒫 A
4 elpwi ⊢ x ∈ 𝒫 A → x ⊆ A
5 3 4 syl ⊢ x ∈ 𝒫 A → x ⊆ A
6 sstr2 ⊢ x ⊆ A → A ⊆ B → x ⊆ B
7 6 impcom ⊢ A ⊆ B ∧ x ⊆ A → x ⊆ B
8 2 5 7 syl2an ⊢ A ⊆ B ∧ x ∈ 𝒫 A → x ⊆ B
9 elpwg ⊢ x ∈ V → x ∈ 𝒫 B ↔ x ⊆ B
10 9 biimpar ⊢ x ∈ V ∧ x ⊆ B → x ∈ 𝒫 B
11 1 8 10 eel021old ⊢ A ⊆ B ∧ x ∈ 𝒫 A → x ∈ 𝒫 B
12 11 ex ⊢ A ⊆ B → x ∈ 𝒫 A → x ∈ 𝒫 B
13 12 alrimiv ⊢ A ⊆ B → ∀ x x ∈ 𝒫 A → x ∈ 𝒫 B
14 df-ss ⊢ 𝒫 A ⊆ 𝒫 B ↔ ∀ x x ∈ 𝒫 A → x ∈ 𝒫 B
15 14 biimpri ⊢ ∀ x x ∈ 𝒫 A → x ∈ 𝒫 B → 𝒫 A ⊆ 𝒫 B
16 13 15 syl ⊢ A ⊆ B → 𝒫 A ⊆ 𝒫 B
17 16 iin1 ⊢ A ⊆ B → 𝒫 A ⊆ 𝒫 B