Metamath Proof Explorer


Theorem subcan2ad

Description: Cancellation law for subtraction. Deduction form of subcan2 . Generalization of subcan2d . (Contributed by David Moews, 28-Feb-2017)

Ref Expression
Hypotheses negidd.1 φA
pncand.2 φB
subaddd.3 φC
Assertion subcan2ad φAC=BCA=B

Proof

Step Hyp Ref Expression
1 negidd.1 φA
2 pncand.2 φB
3 subaddd.3 φC
4 subcan2 ABCAC=BCA=B
5 1 2 3 4 syl3anc φAC=BCA=B