Metamath Proof Explorer


Theorem subneintr2d

Description: Introducing subtraction on both sides of a statement of inequality. Contrapositive of subcan2d . (Contributed by David Moews, 28-Feb-2017)

Ref Expression
Hypotheses negidd.1 ⊢ φ → A ∈ ℂ
pncand.2 ⊢ φ → B ∈ ℂ
subaddd.3 ⊢ φ → C ∈ ℂ
subneintr2d.4 ⊢ φ → A ≠ B
Assertion subneintr2d ⊢ φ → A − C ≠ B − C

Proof

Step Hyp Ref Expression
1 negidd.1 ⊢ φ → A ∈ ℂ
2 pncand.2 ⊢ φ → B ∈ ℂ
3 subaddd.3 ⊢ φ → C ∈ ℂ
4 subneintr2d.4 ⊢ φ → A ≠ B
5 1 2 3 subcan2ad ⊢ φ → A − C = B − C ↔ A = B
6 5 necon3bid ⊢ φ → A − C ≠ B − C ↔ A ≠ B
7 4 6 mpbird ⊢ φ → A − C ≠ B − C