Metamath Proof Explorer


Theorem subcand

Description: Cancellation law for subtraction. (Contributed by Mario Carneiro, 27-May-2016)

Ref Expression
Hypotheses negidd.1 φA
pncand.2 φB
subaddd.3 φC
subcand.4 φAB=AC
Assertion subcand φB=C

Proof

Step Hyp Ref Expression
1 negidd.1 φA
2 pncand.2 φB
3 subaddd.3 φC
4 subcand.4 φAB=AC
5 subcan ABCAB=ACB=C
6 1 2 3 5 syl3anc φAB=ACB=C
7 4 6 mpbid φB=C