Metamath Proof Explorer


Theorem subrfn

Description: Vector subtraction produces a function. (Contributed by Andrew Salmon, 27-Jan-2012)

Ref Expression
Assertion subrfn ⊢ A ∈ C ∧ B ∈ D → A - r B Fn ℝ

Proof

Step Hyp Ref Expression
1 ovex ⊢ A ⁡ x − B ⁡ x ∈ V
2 eqid ⊢ x ∈ ℝ ⟼ A ⁡ x − B ⁡ x = x ∈ ℝ ⟼ A ⁡ x − B ⁡ x
3 1 2 fnmpti ⊢ x ∈ ℝ ⟼ A ⁡ x − B ⁡ x Fn ℝ
4 subrval ⊢ A ∈ C ∧ B ∈ D → A - r B = x ∈ ℝ ⟼ A ⁡ x − B ⁡ x
5 4 fneq1d ⊢ A ∈ C ∧ B ∈ D → A - r B Fn ℝ ↔ x ∈ ℝ ⟼ A ⁡ x − B ⁡ x Fn ℝ
6 3 5 mpbiri ⊢ A ∈ C ∧ B ∈ D → A - r B Fn ℝ