Metamath Proof Explorer


Theorem subsub23i

Description: Swap subtrahend and result of subtraction. (Contributed by NM, 7-Oct-1999)

Ref Expression
Hypotheses negidi.1 ⊢ A ∈ ℂ
pncan3i.2 ⊢ B ∈ ℂ
subadd.3 ⊢ C ∈ ℂ
Assertion subsub23i ⊢ A − B = C ↔ A − C = B

Proof

Step Hyp Ref Expression
1 negidi.1 ⊢ A ∈ ℂ
2 pncan3i.2 ⊢ B ∈ ℂ
3 subadd.3 ⊢ C ∈ ℂ
4 subsub23 ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ C ∈ ℂ → A − B = C ↔ A − C = B
5 1 2 3 4 mp3an ⊢ A − B = C ↔ A − C = B