Metamath Proof Explorer


Theorem tfr2ALT

Description: Alternate proof of tfr2 using well-ordered recursion. (Contributed by Scott Fenton, 3-Aug-2020) (New usage is discouraged.) (Proof modification is discouraged.)

Ref Expression
Hypothesis tfrALT.1 ⊢ F = recs ⁡ G
Assertion tfr2ALT ⊢ A ∈ On → F ⁡ A = G ⁡ F ↾ A

Proof

Step Hyp Ref Expression
1 tfrALT.1 ⊢ F = recs ⁡ G
2 epweon ⊢ E We On
3 epse ⊢ E Se On
4 df-recs ⊢ recs ⁡ G = wrecs ⁡ E On G
5 1 4 eqtri ⊢ F = wrecs ⁡ E On G
6 5 wfr2 ⊢ E We On ∧ E Se On ∧ A ∈ On → F ⁡ A = G ⁡ F ↾ Pred E On A
7 2 3 6 mpanl12 ⊢ A ∈ On → F ⁡ A = G ⁡ F ↾ Pred E On A
8 predon ⊢ A ∈ On → Pred E On A = A
9 8 reseq2d ⊢ A ∈ On → F ↾ Pred E On A = F ↾ A
10 9 fveq2d ⊢ A ∈ On → G ⁡ F ↾ Pred E On A = G ⁡ F ↾ A
11 7 10 eqtrd ⊢ A ∈ On → F ⁡ A = G ⁡ F ↾ A