Metamath Proof Explorer


Theorem tgsss2

Description: Third congruence theorem: SSS. Theorem 11.51 of Schwabhauser p. 109. (Contributed by Thierry Arnoux, 1-Aug-2020)

Ref Expression
Hypotheses tgsas.p ⊢ P = Base G
tgsas.m ⊢ - ˙ = dist ⁡ G
tgsas.i ⊢ I = Itv ⁡ G
tgsas.g ⊢ φ → G ∈ 𝒢 Tarski
tgsas.a ⊢ φ → A ∈ P
tgsas.b ⊢ φ → B ∈ P
tgsas.c ⊢ φ → C ∈ P
tgsas.d ⊢ φ → D ∈ P
tgsas.e ⊢ φ → E ∈ P
tgsas.f ⊢ φ → F ∈ P
tgsss.1 ⊢ φ → A - ˙ B = D - ˙ E
tgsss.2 ⊢ φ → B - ˙ C = E - ˙ F
tgsss.3 ⊢ φ → C - ˙ A = F - ˙ D
tgsss.4 ⊢ φ → A ≠ B
tgsss.5 ⊢ φ → B ≠ C
tgsss.6 ⊢ φ → C ≠ A
Assertion tgsss2 ⊢ φ → ⟨“ CAB ”⟩ ∼ 𝒢 ∠ ⁡ G ⟨“ FDE ”⟩

Proof

Step Hyp Ref Expression
1 tgsas.p ⊢ P = Base G
2 tgsas.m ⊢ - ˙ = dist ⁡ G
3 tgsas.i ⊢ I = Itv ⁡ G
4 tgsas.g ⊢ φ → G ∈ 𝒢 Tarski
5 tgsas.a ⊢ φ → A ∈ P
6 tgsas.b ⊢ φ → B ∈ P
7 tgsas.c ⊢ φ → C ∈ P
8 tgsas.d ⊢ φ → D ∈ P
9 tgsas.e ⊢ φ → E ∈ P
10 tgsas.f ⊢ φ → F ∈ P
11 tgsss.1 ⊢ φ → A - ˙ B = D - ˙ E
12 tgsss.2 ⊢ φ → B - ˙ C = E - ˙ F
13 tgsss.3 ⊢ φ → C - ˙ A = F - ˙ D
14 tgsss.4 ⊢ φ → A ≠ B
15 tgsss.5 ⊢ φ → B ≠ C
16 tgsss.6 ⊢ φ → C ≠ A
17 1 2 3 4 7 5 6 10 8 9 13 11 12 16 14 15 tgsss1 ⊢ φ → ⟨“ CAB ”⟩ ∼ 𝒢 ∠ ⁡ G ⟨“ FDE ”⟩