Metamath Proof Explorer


Theorem tposeq

Description: Equality theorem for transposition. (Contributed by Mario Carneiro, 10-Sep-2015)

Ref Expression
Assertion tposeq ⊢ F = G → tpos F = tpos G

Proof

Step Hyp Ref Expression
1 eqimss ⊢ F = G → F ⊆ G
2 tposss ⊢ F ⊆ G → tpos F ⊆ tpos G
3 1 2 syl ⊢ F = G → tpos F ⊆ tpos G
4 eqimss2 ⊢ F = G → G ⊆ F
5 tposss ⊢ G ⊆ F → tpos G ⊆ tpos F
6 4 5 syl ⊢ F = G → tpos G ⊆ tpos F
7 3 6 eqssd ⊢ F = G → tpos F = tpos G