Metamath Proof Explorer


Theorem tposfn

Description: Functionality of a transposition. (Contributed by Mario Carneiro, 4-Oct-2015)

Ref Expression
Assertion tposfn ⊢ F Fn A × B → tpos F Fn B × A

Proof

Step Hyp Ref Expression
1 tposf ⊢ F : A × B ⟶ V → tpos F : B × A ⟶ V
2 dffn2 ⊢ F Fn A × B ↔ F : A × B ⟶ V
3 dffn2 ⊢ tpos F Fn B × A ↔ tpos F : B × A ⟶ V
4 1 2 3 3imtr4i ⊢ F Fn A × B → tpos F Fn B × A