Metamath Proof Explorer


Theorem xp2nd

Description: Location of the second element of a Cartesian product. (Contributed by Jeff Madsen, 2-Sep-2009)

Ref Expression
Assertion xp2nd ⊢ A ∈ B × C → 2 nd ⁡ A ∈ C

Proof

Step Hyp Ref Expression
1 elxp ⊢ A ∈ B × C ↔ ∃ b ∃ c A = b c ∧ b ∈ B ∧ c ∈ C
2 vex ⊢ b ∈ V
3 vex ⊢ c ∈ V
4 2 3 op2ndd ⊢ A = b c → 2 nd ⁡ A = c
5 4 eleq1d ⊢ A = b c → 2 nd ⁡ A ∈ C ↔ c ∈ C
6 5 biimpar ⊢ A = b c ∧ c ∈ C → 2 nd ⁡ A ∈ C
7 6 adantrl ⊢ A = b c ∧ b ∈ B ∧ c ∈ C → 2 nd ⁡ A ∈ C
8 7 exlimivv ⊢ ∃ b ∃ c A = b c ∧ b ∈ B ∧ c ∈ C → 2 nd ⁡ A ∈ C
9 1 8 sylbi ⊢ A ∈ B × C → 2 nd ⁡ A ∈ C