Metamath Proof Explorer


Theorem xpsntpg

Description: The Cartesian product of a singleton and an unordered triple. (Contributed by AV, 18-Aug-2026)

Ref Expression
Assertion xpsntpg ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ U ∧ D ∈ T → A × B C D = A B A C A D

Proof

Step Hyp Ref Expression
1 xpsng ⊢ A ∈ V ∧ B ∈ W → A × B = A B
2 1 adantr ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ U ∧ D ∈ T → A × B = A B
3 xpsng ⊢ A ∈ V ∧ C ∈ U → A × C = A C
4 3 ad2ant2r ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ U ∧ D ∈ T → A × C = A C
5 2 4 uneq12d ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ U ∧ D ∈ T → A × B ∪ A × C = A B ∪ A C
6 xpsng ⊢ A ∈ V ∧ D ∈ T → A × D = A D
7 6 ad2ant2rl ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ U ∧ D ∈ T → A × D = A D
8 5 7 uneq12d ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ U ∧ D ∈ T → A × B ∪ A × C ∪ A × D = A B ∪ A C ∪ A D
9 df-tp ⊢ B C D = B C ∪ D
10 9 xpeq2i ⊢ A × B C D = A × B C ∪ D
11 xpundi ⊢ A × B C ∪ D = A × B C ∪ A × D
12 df-pr ⊢ B C = B ∪ C
13 12 xpeq2i ⊢ A × B C = A × B ∪ C
14 xpundi ⊢ A × B ∪ C = A × B ∪ A × C
15 13 14 eqtri ⊢ A × B C = A × B ∪ A × C
16 15 uneq1i ⊢ A × B C ∪ A × D = A × B ∪ A × C ∪ A × D
17 11 16 eqtri ⊢ A × B C ∪ D = A × B ∪ A × C ∪ A × D
18 10 17 eqtri ⊢ A × B C D = A × B ∪ A × C ∪ A × D
19 df-tp ⊢ A B A C A D = A B A C ∪ A D
20 df-pr ⊢ A B A C = A B ∪ A C
21 20 uneq1i ⊢ A B A C ∪ A D = A B ∪ A C ∪ A D
22 19 21 eqtri ⊢ A B A C A D = A B ∪ A C ∪ A D
23 8 18 22 3eqtr4g ⊢ A ∈ V ∧ B ∈ W ∧ C ∈ U ∧ D ∈ T → A × B C D = A B A C A D