Metamath Proof Explorer


Theorem xrninxp

Description: Intersection of a range Cartesian product with a Cartesian product. (Contributed by Peter Mazsa, 7-Apr-2020)

Ref Expression
Assertion xrninxp ⊢ R ⋉ S ∩ A × B × C = y z u | y ∈ B ∧ z ∈ C ∧ u ∈ A ∧ u R ⋉ S y z -1

Proof

Step Hyp Ref Expression
1 inxp2 ⊢ R ⋉ S ∩ A × B × C = u x | u ∈ A ∧ x ∈ B × C ∧ u R ⋉ S x
2 df-3an ⊢ u ∈ A ∧ x ∈ B × C ∧ u R ⋉ S x ↔ u ∈ A ∧ x ∈ B × C ∧ u R ⋉ S x
3 3anan12 ⊢ u ∈ A ∧ x ∈ B × C ∧ u R ⋉ S x ↔ x ∈ B × C ∧ u ∈ A ∧ u R ⋉ S x
4 2 3 bitr3i ⊢ u ∈ A ∧ x ∈ B × C ∧ u R ⋉ S x ↔ x ∈ B × C ∧ u ∈ A ∧ u R ⋉ S x
5 4 opabbii ⊢ u x | u ∈ A ∧ x ∈ B × C ∧ u R ⋉ S x = u x | x ∈ B × C ∧ u ∈ A ∧ u R ⋉ S x
6 1 5 eqtri ⊢ R ⋉ S ∩ A × B × C = u x | x ∈ B × C ∧ u ∈ A ∧ u R ⋉ S x
7 cnvopab ⊢ x u | x ∈ B × C ∧ u ∈ A ∧ u R ⋉ S x -1 = u x | x ∈ B × C ∧ u ∈ A ∧ u R ⋉ S x
8 breq2 ⊢ x = y z → u R ⋉ S x ↔ u R ⋉ S y z
9 8 anbi2d ⊢ x = y z → u ∈ A ∧ u R ⋉ S x ↔ u ∈ A ∧ u R ⋉ S y z
10 9 dfoprab4 ⊢ x u | x ∈ B × C ∧ u ∈ A ∧ u R ⋉ S x = y z u | y ∈ B ∧ z ∈ C ∧ u ∈ A ∧ u R ⋉ S y z
11 10 cnveqi ⊢ x u | x ∈ B × C ∧ u ∈ A ∧ u R ⋉ S x -1 = y z u | y ∈ B ∧ z ∈ C ∧ u ∈ A ∧ u R ⋉ S y z -1
12 6 7 11 3eqtr2i ⊢ R ⋉ S ∩ A × B × C = y z u | y ∈ B ∧ z ∈ C ∧ u ∈ A ∧ u R ⋉ S y z -1