Metamath Proof Explorer


Theorem 0elros

Description: A ring of sets contains the empty set. (Contributed by Thierry Arnoux, 18-Jul-2020)

Ref Expression
Hypothesis isros.1 ⊢ 𝑄 = { 𝑠 ∈ 𝒫 𝒫 𝑂 ∣ ( ∅ ∈ 𝑠 ∧ ∀ 𝑥 ∈ 𝑠 ∀ 𝑦 ∈ 𝑠 ( ( 𝑥 ∪ 𝑦 ) ∈ 𝑠 ∧ ( 𝑥 ∖ 𝑦 ) ∈ 𝑠 ) ) }
Assertion 0elros ( 𝑆 ∈ 𝑄 → ∅ ∈ 𝑆 )

Proof

Step Hyp Ref Expression
1 isros.1 ⊢ 𝑄 = { 𝑠 ∈ 𝒫 𝒫 𝑂 ∣ ( ∅ ∈ 𝑠 ∧ ∀ 𝑥 ∈ 𝑠 ∀ 𝑦 ∈ 𝑠 ( ( 𝑥 ∪ 𝑦 ) ∈ 𝑠 ∧ ( 𝑥 ∖ 𝑦 ) ∈ 𝑠 ) ) }
2 1 isros ⊢ ( 𝑆 ∈ 𝑄 ↔ ( 𝑆 ∈ 𝒫 𝒫 𝑂 ∧ ∅ ∈ 𝑆 ∧ ∀ 𝑢 ∈ 𝑆 ∀ 𝑣 ∈ 𝑆 ( ( 𝑢 ∪ 𝑣 ) ∈ 𝑆 ∧ ( 𝑢 ∖ 𝑣 ) ∈ 𝑆 ) ) )
3 2 simp2bi ⊢ ( 𝑆 ∈ 𝑄 → ∅ ∈ 𝑆 )