Metamath Proof Explorer


Theorem 0funcg

Description: The functor from the empty category. Corollary of Definition 3.47 of Adamek p. 40, Definition 7.1 of Adamek p. 101, Example 3.3(4.c) of Adamek p. 24, and Example 7.2(3) of Adamek p. 101. (Contributed by Zhi Wang, 17-Oct-2025)

Ref Expression
Hypotheses 0funcg.c ( 𝜑𝐶𝑉 )
0funcg.b ( 𝜑 → ∅ = ( Base ‘ 𝐶 ) )
0funcg.d ( 𝜑𝐷 ∈ Cat )
Assertion 0funcg ( 𝜑 → ( 𝐶 Func 𝐷 ) = { ⟨ ∅ , ∅ ⟩ } )

Proof

Step Hyp Ref Expression
1 0funcg.c ( 𝜑𝐶𝑉 )
2 0funcg.b ( 𝜑 → ∅ = ( Base ‘ 𝐶 ) )
3 0funcg.d ( 𝜑𝐷 ∈ Cat )
4 relfunc Rel ( 𝐶 Func 𝐷 )
5 0ex ∅ ∈ V
6 5 5 relsnop Rel { ⟨ ∅ , ∅ ⟩ }
7 1 2 3 0funcg2 ( 𝜑 → ( 𝑓 ( 𝐶 Func 𝐷 ) 𝑔 ↔ ( 𝑓 = ∅ ∧ 𝑔 = ∅ ) ) )
8 brsnop ( ( ∅ ∈ V ∧ ∅ ∈ V ) → ( 𝑓 { ⟨ ∅ , ∅ ⟩ } 𝑔 ↔ ( 𝑓 = ∅ ∧ 𝑔 = ∅ ) ) )
9 5 5 8 mp2an ( 𝑓 { ⟨ ∅ , ∅ ⟩ } 𝑔 ↔ ( 𝑓 = ∅ ∧ 𝑔 = ∅ ) )
10 7 9 bitr4di ( 𝜑 → ( 𝑓 ( 𝐶 Func 𝐷 ) 𝑔𝑓 { ⟨ ∅ , ∅ ⟩ } 𝑔 ) )
11 4 6 10 eqbrrdiv ( 𝜑 → ( 𝐶 Func 𝐷 ) = { ⟨ ∅ , ∅ ⟩ } )