Metamath Proof Explorer


Theorem 0sgm

Description: The value of the sum-of-divisors function, usually denoted σ0(n). (Contributed by Mario Carneiro, 21-Jun-2015)

Ref Expression
Assertion 0sgm ( 𝐴 ∈ ℕ → ( 0 σ 𝐴 ) = ( ♯ ‘ { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } ) )

Proof

Step Hyp Ref Expression
1 0z 0 ∈ ℤ
2 sgmval2 ( ( 0 ∈ ℤ ∧ 𝐴 ∈ ℕ ) → ( 0 σ 𝐴 ) = Σ 𝑘 ∈ { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } ( 𝑘 ↑ 0 ) )
3 1 2 mpan ( 𝐴 ∈ ℕ → ( 0 σ 𝐴 ) = Σ 𝑘 ∈ { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } ( 𝑘 ↑ 0 ) )
4 elrabi ( 𝑘 ∈ { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } → 𝑘 ∈ ℕ )
5 4 nncnd ( 𝑘 ∈ { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } → 𝑘 ∈ ℂ )
6 5 exp0d ( 𝑘 ∈ { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } → ( 𝑘 ↑ 0 ) = 1 )
7 6 sumeq2i Σ 𝑘 ∈ { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } ( 𝑘 ↑ 0 ) = Σ 𝑘 ∈ { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } 1
8 fzfid ( 𝐴 ∈ ℕ → ( 1 ... 𝐴 ) ∈ Fin )
9 dvdsssfz1 ( 𝐴 ∈ ℕ → { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } ⊆ ( 1 ... 𝐴 ) )
10 8 9 ssfid ( 𝐴 ∈ ℕ → { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } ∈ Fin )
11 ax-1cn 1 ∈ ℂ
12 fsumconst ( ( { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } ∈ Fin ∧ 1 ∈ ℂ ) → Σ 𝑘 ∈ { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } 1 = ( ( ♯ ‘ { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } ) · 1 ) )
13 10 11 12 sylancl ( 𝐴 ∈ ℕ → Σ 𝑘 ∈ { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } 1 = ( ( ♯ ‘ { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } ) · 1 ) )
14 7 13 syl5eq ( 𝐴 ∈ ℕ → Σ 𝑘 ∈ { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } ( 𝑘 ↑ 0 ) = ( ( ♯ ‘ { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } ) · 1 ) )
15 hashcl ( { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } ∈ Fin → ( ♯ ‘ { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } ) ∈ ℕ0 )
16 10 15 syl ( 𝐴 ∈ ℕ → ( ♯ ‘ { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } ) ∈ ℕ0 )
17 16 nn0cnd ( 𝐴 ∈ ℕ → ( ♯ ‘ { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } ) ∈ ℂ )
18 17 mulid1d ( 𝐴 ∈ ℕ → ( ( ♯ ‘ { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } ) · 1 ) = ( ♯ ‘ { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } ) )
19 3 14 18 3eqtrd ( 𝐴 ∈ ℕ → ( 0 σ 𝐴 ) = ( ♯ ‘ { 𝑝 ∈ ℕ ∣ 𝑝𝐴 } ) )