Metamath Proof Explorer


Theorem abanssl

Description: A class abstraction with a conjunction is a subset of the class abstraction with the left conjunct only. (Contributed by AV, 7-Aug-2024) (Proof shortened by SN, 22-Aug-2024)

Ref Expression
Assertion abanssl { 𝑥 ∣ ( 𝜑 ∧ 𝜓 ) } ⊆ { 𝑥 ∣ 𝜑 }

Proof

Step Hyp Ref Expression
1 simpl ⊢ ( ( 𝜑 ∧ 𝜓 ) → 𝜑 )
2 1 ss2abi ⊢ { 𝑥 ∣ ( 𝜑 ∧ 𝜓 ) } ⊆ { 𝑥 ∣ 𝜑 }