Metamath Proof Explorer


Theorem ablcomd

Description: An abelian group operation is commutative, deduction version. (Contributed by Thierry Arnoux, 15-Feb-2026)

Ref Expression
Hypotheses ablcomd.1 𝐵 = ( Base ‘ 𝐺 )
ablcomd.2 + = ( +g𝐺 )
ablcomd.3 ( 𝜑𝐺 ∈ Abel )
ablcomd.4 ( 𝜑𝑋𝐵 )
ablcomd.5 ( 𝜑𝑌𝐵 )
Assertion ablcomd ( 𝜑 → ( 𝑋 + 𝑌 ) = ( 𝑌 + 𝑋 ) )

Proof

Step Hyp Ref Expression
1 ablcomd.1 𝐵 = ( Base ‘ 𝐺 )
2 ablcomd.2 + = ( +g𝐺 )
3 ablcomd.3 ( 𝜑𝐺 ∈ Abel )
4 ablcomd.4 ( 𝜑𝑋𝐵 )
5 ablcomd.5 ( 𝜑𝑌𝐵 )
6 1 2 ablcom ( ( 𝐺 ∈ Abel ∧ 𝑋𝐵𝑌𝐵 ) → ( 𝑋 + 𝑌 ) = ( 𝑌 + 𝑋 ) )
7 3 4 5 6 syl3anc ( 𝜑 → ( 𝑋 + 𝑌 ) = ( 𝑌 + 𝑋 ) )