Metamath Proof Explorer
Description: Deduction adding conjuncts to antecedent. (Contributed by Alan Sare, 17-Oct-2017) (Proof shortened by Wolf Lammen, 23-Jun-2022)
|
|
Ref |
Expression |
|
Hypothesis |
ad5ant.1 |
⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → 𝜃 ) |
|
Assertion |
ad5ant125 |
⊢ ( ( ( ( ( 𝜑 ∧ 𝜓 ) ∧ 𝜏 ) ∧ 𝜂 ) ∧ 𝜒 ) → 𝜃 ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
ad5ant.1 |
⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → 𝜃 ) |
| 2 |
1
|
3expia |
⊢ ( ( 𝜑 ∧ 𝜓 ) → ( 𝜒 → 𝜃 ) ) |
| 3 |
2
|
2a1d |
⊢ ( ( 𝜑 ∧ 𝜓 ) → ( 𝜏 → ( 𝜂 → ( 𝜒 → 𝜃 ) ) ) ) |
| 4 |
3
|
imp41 |
⊢ ( ( ( ( ( 𝜑 ∧ 𝜓 ) ∧ 𝜏 ) ∧ 𝜂 ) ∧ 𝜒 ) → 𝜃 ) |