Metamath Proof Explorer


Theorem aibnbaif

Description: Given a implies b, not b, there exists a proof for a is F. (Contributed by Jarvin Udandy, 1-Sep-2016)

Ref Expression
Hypotheses aibnbaif.1 ⊢ ( 𝜑 → 𝜓 )
aibnbaif.2 ⊢ ¬ 𝜓
Assertion aibnbaif ( 𝜑 ↔ ⊥ )

Proof

Step Hyp Ref Expression
1 aibnbaif.1 ⊢ ( 𝜑 → 𝜓 )
2 aibnbaif.2 ⊢ ¬ 𝜓
3 1 2 aibnbna ⊢ ¬ 𝜑
4 3 bifal ⊢ ( 𝜑 ↔ ⊥ )