Metamath Proof Explorer


Theorem anandi

Description: Distribution of conjunction over conjunction. (Contributed by NM, 14-Aug-1995)

Ref Expression
Assertion anandi ( ( 𝜑 ∧ ( 𝜓 ∧ 𝜒 ) ) ↔ ( ( 𝜑 ∧ 𝜓 ) ∧ ( 𝜑 ∧ 𝜒 ) ) )

Proof

Step Hyp Ref Expression
1 anidm ⊢ ( ( 𝜑 ∧ 𝜑 ) ↔ 𝜑 )
2 1 anbi1i ⊢ ( ( ( 𝜑 ∧ 𝜑 ) ∧ ( 𝜓 ∧ 𝜒 ) ) ↔ ( 𝜑 ∧ ( 𝜓 ∧ 𝜒 ) ) )
3 an4 ⊢ ( ( ( 𝜑 ∧ 𝜑 ) ∧ ( 𝜓 ∧ 𝜒 ) ) ↔ ( ( 𝜑 ∧ 𝜓 ) ∧ ( 𝜑 ∧ 𝜒 ) ) )
4 2 3 bitr3i ⊢ ( ( 𝜑 ∧ ( 𝜓 ∧ 𝜒 ) ) ↔ ( ( 𝜑 ∧ 𝜓 ) ∧ ( 𝜑 ∧ 𝜒 ) ) )