Metamath Proof Explorer


Theorem ancom

Description: Commutative law for conjunction. Theorem *4.3 of WhiteheadRussell p. 118. (Contributed by NM, 25-Jun-1998) (Proof shortened by Wolf Lammen, 4-Nov-2012)

Ref Expression
Assertion ancom ( ( 𝜑 ∧ 𝜓 ) ↔ ( 𝜓 ∧ 𝜑 ) )

Proof

Step Hyp Ref Expression
1 pm3.22 ⊢ ( ( 𝜑 ∧ 𝜓 ) → ( 𝜓 ∧ 𝜑 ) )
2 pm3.22 ⊢ ( ( 𝜓 ∧ 𝜑 ) → ( 𝜑 ∧ 𝜓 ) )
3 1 2 impbii ⊢ ( ( 𝜑 ∧ 𝜓 ) ↔ ( 𝜓 ∧ 𝜑 ) )