Metamath Proof Explorer


Theorem aspssid

Description: A set of vectors is a subset of its span. ( spanss2 analog.) (Contributed by Mario Carneiro, 7-Jan-2015)

Ref Expression
Hypotheses aspval.a ⊢ 𝐴 = ( AlgSpan ‘ 𝑊 )
aspval.v ⊢ 𝑉 = ( Base ‘ 𝑊 )
Assertion aspssid ( ( 𝑊 ∈ AssAlg ∧ 𝑆 ⊆ 𝑉 ) → 𝑆 ⊆ ( 𝐴 ‘ 𝑆 ) )

Proof

Step Hyp Ref Expression
1 aspval.a ⊢ 𝐴 = ( AlgSpan ‘ 𝑊 )
2 aspval.v ⊢ 𝑉 = ( Base ‘ 𝑊 )
3 ssintub ⊢ 𝑆 ⊆ ∩ { 𝑡 ∈ ( ( SubRing ‘ 𝑊 ) ∩ ( LSubSp ‘ 𝑊 ) ) ∣ 𝑆 ⊆ 𝑡 }
4 eqid ⊢ ( LSubSp ‘ 𝑊 ) = ( LSubSp ‘ 𝑊 )
5 1 2 4 aspval ⊢ ( ( 𝑊 ∈ AssAlg ∧ 𝑆 ⊆ 𝑉 ) → ( 𝐴 ‘ 𝑆 ) = ∩ { 𝑡 ∈ ( ( SubRing ‘ 𝑊 ) ∩ ( LSubSp ‘ 𝑊 ) ) ∣ 𝑆 ⊆ 𝑡 } )
6 3 5 sseqtrrid ⊢ ( ( 𝑊 ∈ AssAlg ∧ 𝑆 ⊆ 𝑉 ) → 𝑆 ⊆ ( 𝐴 ‘ 𝑆 ) )