Metamath Proof Explorer


Theorem axpowg

Description: A generalization of ax-pow that combines it and zfpow into a single theorem scheme. Unlike ax-pow , this scheme lacks a distinct variable condition for y and w . (Contributed by BTernaryTau, 26-May-2026)

Ref Expression
Assertion axpowg ∃ 𝑦 ∀ 𝑧 ( ∀ 𝑤 ( 𝑤 ∈ 𝑧 → 𝑤 ∈ 𝑥 ) → 𝑧 ∈ 𝑦 )

Proof

Step Hyp Ref Expression
1 ax-pow ⊢ ∃ 𝑦 ∀ 𝑧 ( ∀ 𝑣 ( 𝑣 ∈ 𝑧 → 𝑣 ∈ 𝑥 ) → 𝑧 ∈ 𝑦 )
2 elequ1 ⊢ ( 𝑣 = 𝑤 → ( 𝑣 ∈ 𝑧 ↔ 𝑤 ∈ 𝑧 ) )
3 elequ1 ⊢ ( 𝑣 = 𝑤 → ( 𝑣 ∈ 𝑥 ↔ 𝑤 ∈ 𝑥 ) )
4 2 3 imbi12d ⊢ ( 𝑣 = 𝑤 → ( ( 𝑣 ∈ 𝑧 → 𝑣 ∈ 𝑥 ) ↔ ( 𝑤 ∈ 𝑧 → 𝑤 ∈ 𝑥 ) ) )
5 4 cbvalvw ⊢ ( ∀ 𝑣 ( 𝑣 ∈ 𝑧 → 𝑣 ∈ 𝑥 ) ↔ ∀ 𝑤 ( 𝑤 ∈ 𝑧 → 𝑤 ∈ 𝑥 ) )
6 5 imbi1i ⊢ ( ( ∀ 𝑣 ( 𝑣 ∈ 𝑧 → 𝑣 ∈ 𝑥 ) → 𝑧 ∈ 𝑦 ) ↔ ( ∀ 𝑤 ( 𝑤 ∈ 𝑧 → 𝑤 ∈ 𝑥 ) → 𝑧 ∈ 𝑦 ) )
7 6 albii ⊢ ( ∀ 𝑧 ( ∀ 𝑣 ( 𝑣 ∈ 𝑧 → 𝑣 ∈ 𝑥 ) → 𝑧 ∈ 𝑦 ) ↔ ∀ 𝑧 ( ∀ 𝑤 ( 𝑤 ∈ 𝑧 → 𝑤 ∈ 𝑥 ) → 𝑧 ∈ 𝑦 ) )
8 7 exbii ⊢ ( ∃ 𝑦 ∀ 𝑧 ( ∀ 𝑣 ( 𝑣 ∈ 𝑧 → 𝑣 ∈ 𝑥 ) → 𝑧 ∈ 𝑦 ) ↔ ∃ 𝑦 ∀ 𝑧 ( ∀ 𝑤 ( 𝑤 ∈ 𝑧 → 𝑤 ∈ 𝑥 ) → 𝑧 ∈ 𝑦 ) )
9 1 8 mpbi ⊢ ∃ 𝑦 ∀ 𝑧 ( ∀ 𝑤 ( 𝑤 ∈ 𝑧 → 𝑤 ∈ 𝑥 ) → 𝑧 ∈ 𝑦 )