Metamath Proof Explorer


Theorem bj-hbext

Description: Closed form of bj-hbex and hbex . (Contributed by BJ, 10-Oct-2019)

Ref Expression
Assertion bj-hbext ( ∀ 𝑦𝑥 ( 𝜑 → ∀ 𝑥 𝜓 ) → ( ∃ 𝑦 𝜑 → ∀ 𝑥𝑦 𝜓 ) )

Proof

Step Hyp Ref Expression
1 id ( ∀ 𝑦𝑥 ( 𝜑 → ∀ 𝑥 𝜓 ) → ∀ 𝑦𝑥 ( 𝜑 → ∀ 𝑥 𝜓 ) )
2 sp ( ∀ 𝑥 ( 𝜑 → ∀ 𝑥 𝜓 ) → ( 𝜑 → ∀ 𝑥 𝜓 ) )
3 1 2 bj-hbexd ( ∀ 𝑦𝑥 ( 𝜑 → ∀ 𝑥 𝜓 ) → ( ∃ 𝑦 𝜑 → ∀ 𝑥𝑦 𝜓 ) )