Metamath Proof Explorer


Theorem hbex

Description: If x is not free in ph , it is not free in E. y ph . (Contributed by NM, 12-Mar-1993) Reduce symbol count in nfex , hbex . (Revised by Wolf Lammen, 16-Oct-2021)

Ref Expression
Hypothesis hbex.1 ( 𝜑 → ∀ 𝑥 𝜑 )
Assertion hbex ( ∃ 𝑦 𝜑 → ∀ 𝑥𝑦 𝜑 )

Proof

Step Hyp Ref Expression
1 hbex.1 ( 𝜑 → ∀ 𝑥 𝜑 )
2 1 nf5i 𝑥 𝜑
3 2 nfex 𝑥𝑦 𝜑
4 3 nf5ri ( ∃ 𝑦 𝜑 → ∀ 𝑥𝑦 𝜑 )