Metamath Proof Explorer


Theorem brvbrvvdif

Description: Binary relation with the complement under the universal class of ordered pairs is the same as with universal complement. (Contributed by Peter Mazsa, 28-Nov-2018)

Ref Expression
Assertion brvbrvvdif ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) → ( 𝐴 ( ( V × V ) ∖ 𝑅 ) 𝐵 ↔ 𝐴 ( V ∖ 𝑅 ) 𝐵 ) )

Proof

Step Hyp Ref Expression
1 brvvdif ⊢ ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) → ( 𝐴 ( ( V × V ) ∖ 𝑅 ) 𝐵 ↔ ¬ 𝐴 𝑅 𝐵 ) )
2 brvdif ⊢ ( 𝐴 ( V ∖ 𝑅 ) 𝐵 ↔ ¬ 𝐴 𝑅 𝐵 )
3 1 2 bitr4di ⊢ ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) → ( 𝐴 ( ( V × V ) ∖ 𝑅 ) 𝐵 ↔ 𝐴 ( V ∖ 𝑅 ) 𝐵 ) )