Metamath Proof Explorer


Theorem chj12i

Description: A rearrangement of Hilbert lattice join. (Contributed by NM, 29-Apr-2006) (New usage is discouraged.)

Ref Expression
Hypotheses chj12.1 ⊢ 𝐴 ∈ Cℋ
chj12.2 ⊢ 𝐵 ∈ Cℋ
chj12.3 ⊢ 𝐶 ∈ Cℋ
Assertion chj12i ( 𝐴 ∨ℋ ( 𝐵 ∨ℋ 𝐶 ) ) = ( 𝐵 ∨ℋ ( 𝐴 ∨ℋ 𝐶 ) )

Proof

Step Hyp Ref Expression
1 chj12.1 ⊢ 𝐴 ∈ Cℋ
2 chj12.2 ⊢ 𝐵 ∈ Cℋ
3 chj12.3 ⊢ 𝐶 ∈ Cℋ
4 1 2 chjcomi ⊢ ( 𝐴 ∨ℋ 𝐵 ) = ( 𝐵 ∨ℋ 𝐴 )
5 4 oveq1i ⊢ ( ( 𝐴 ∨ℋ 𝐵 ) ∨ℋ 𝐶 ) = ( ( 𝐵 ∨ℋ 𝐴 ) ∨ℋ 𝐶 )
6 1 2 3 chjassi ⊢ ( ( 𝐴 ∨ℋ 𝐵 ) ∨ℋ 𝐶 ) = ( 𝐴 ∨ℋ ( 𝐵 ∨ℋ 𝐶 ) )
7 2 1 3 chjassi ⊢ ( ( 𝐵 ∨ℋ 𝐴 ) ∨ℋ 𝐶 ) = ( 𝐵 ∨ℋ ( 𝐴 ∨ℋ 𝐶 ) )
8 5 6 7 3eqtr3i ⊢ ( 𝐴 ∨ℋ ( 𝐵 ∨ℋ 𝐶 ) ) = ( 𝐵 ∨ℋ ( 𝐴 ∨ℋ 𝐶 ) )