Metamath Proof Explorer


Theorem csbied2

Description: Conversion of implicit substitution to explicit class substitution, deduction form. (Contributed by Mario Carneiro, 2-Jan-2017)

Ref Expression
Hypotheses csbied2.1 ⊢ ( 𝜑 → 𝐴 ∈ 𝑉 )
csbied2.2 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
csbied2.3 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝐵 ) → 𝐶 = 𝐷 )
Assertion csbied2 ( 𝜑 → ⦋ 𝐴 / 𝑥 ⦌ 𝐶 = 𝐷 )

Proof

Step Hyp Ref Expression
1 csbied2.1 ⊢ ( 𝜑 → 𝐴 ∈ 𝑉 )
2 csbied2.2 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
3 csbied2.3 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝐵 ) → 𝐶 = 𝐷 )
4 id ⊢ ( 𝑥 = 𝐴 → 𝑥 = 𝐴 )
5 4 2 sylan9eqr ⊢ ( ( 𝜑 ∧ 𝑥 = 𝐴 ) → 𝑥 = 𝐵 )
6 5 3 syldan ⊢ ( ( 𝜑 ∧ 𝑥 = 𝐴 ) → 𝐶 = 𝐷 )
7 1 6 csbied ⊢ ( 𝜑 → ⦋ 𝐴 / 𝑥 ⦌ 𝐶 = 𝐷 )