Metamath Proof Explorer


Theorem cutbday

Description: The birthday of the surreal cut is equal to the minimum birthday in the gap. (Contributed by Scott Fenton, 8-Dec-2021)

Ref Expression
Assertion cutbday ( 𝐴 <<s 𝐵 → ( bday ‘ ( 𝐴 |s 𝐵 ) ) = ∩ ( bday “ { 𝑥 ∈ No ∣ ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) } ) )

Proof

Step Hyp Ref Expression
1 cutsval ⊢ ( 𝐴 <<s 𝐵 → ( 𝐴 |s 𝐵 ) = ( ℩ 𝑦 ∈ { 𝑥 ∈ No ∣ ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) } ( bday ‘ 𝑦 ) = ∩ ( bday “ { 𝑥 ∈ No ∣ ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) } ) ) )
2 1 eqcomd ⊢ ( 𝐴 <<s 𝐵 → ( ℩ 𝑦 ∈ { 𝑥 ∈ No ∣ ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) } ( bday ‘ 𝑦 ) = ∩ ( bday “ { 𝑥 ∈ No ∣ ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) } ) ) = ( 𝐴 |s 𝐵 ) )
3 cutcuts ⊢ ( 𝐴 <<s 𝐵 → ( ( 𝐴 |s 𝐵 ) ∈ No ∧ 𝐴 <<s { ( 𝐴 |s 𝐵 ) } ∧ { ( 𝐴 |s 𝐵 ) } <<s 𝐵 ) )
4 sneq ⊢ ( 𝑥 = ( 𝐴 |s 𝐵 ) → { 𝑥 } = { ( 𝐴 |s 𝐵 ) } )
5 4 breq2d ⊢ ( 𝑥 = ( 𝐴 |s 𝐵 ) → ( 𝐴 <<s { 𝑥 } ↔ 𝐴 <<s { ( 𝐴 |s 𝐵 ) } ) )
6 4 breq1d ⊢ ( 𝑥 = ( 𝐴 |s 𝐵 ) → ( { 𝑥 } <<s 𝐵 ↔ { ( 𝐴 |s 𝐵 ) } <<s 𝐵 ) )
7 5 6 anbi12d ⊢ ( 𝑥 = ( 𝐴 |s 𝐵 ) → ( ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) ↔ ( 𝐴 <<s { ( 𝐴 |s 𝐵 ) } ∧ { ( 𝐴 |s 𝐵 ) } <<s 𝐵 ) ) )
8 7 elrab ⊢ ( ( 𝐴 |s 𝐵 ) ∈ { 𝑥 ∈ No ∣ ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) } ↔ ( ( 𝐴 |s 𝐵 ) ∈ No ∧ ( 𝐴 <<s { ( 𝐴 |s 𝐵 ) } ∧ { ( 𝐴 |s 𝐵 ) } <<s 𝐵 ) ) )
9 3anass ⊢ ( ( ( 𝐴 |s 𝐵 ) ∈ No ∧ 𝐴 <<s { ( 𝐴 |s 𝐵 ) } ∧ { ( 𝐴 |s 𝐵 ) } <<s 𝐵 ) ↔ ( ( 𝐴 |s 𝐵 ) ∈ No ∧ ( 𝐴 <<s { ( 𝐴 |s 𝐵 ) } ∧ { ( 𝐴 |s 𝐵 ) } <<s 𝐵 ) ) )
10 8 9 bitr4i ⊢ ( ( 𝐴 |s 𝐵 ) ∈ { 𝑥 ∈ No ∣ ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) } ↔ ( ( 𝐴 |s 𝐵 ) ∈ No ∧ 𝐴 <<s { ( 𝐴 |s 𝐵 ) } ∧ { ( 𝐴 |s 𝐵 ) } <<s 𝐵 ) )
11 3 10 sylibr ⊢ ( 𝐴 <<s 𝐵 → ( 𝐴 |s 𝐵 ) ∈ { 𝑥 ∈ No ∣ ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) } )
12 conway ⊢ ( 𝐴 <<s 𝐵 → ∃! 𝑦 ∈ { 𝑥 ∈ No ∣ ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) } ( bday ‘ 𝑦 ) = ∩ ( bday “ { 𝑥 ∈ No ∣ ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) } ) )
13 fveqeq2 ⊢ ( 𝑦 = ( 𝐴 |s 𝐵 ) → ( ( bday ‘ 𝑦 ) = ∩ ( bday “ { 𝑥 ∈ No ∣ ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) } ) ↔ ( bday ‘ ( 𝐴 |s 𝐵 ) ) = ∩ ( bday “ { 𝑥 ∈ No ∣ ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) } ) ) )
14 13 riota2 ⊢ ( ( ( 𝐴 |s 𝐵 ) ∈ { 𝑥 ∈ No ∣ ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) } ∧ ∃! 𝑦 ∈ { 𝑥 ∈ No ∣ ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) } ( bday ‘ 𝑦 ) = ∩ ( bday “ { 𝑥 ∈ No ∣ ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) } ) ) → ( ( bday ‘ ( 𝐴 |s 𝐵 ) ) = ∩ ( bday “ { 𝑥 ∈ No ∣ ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) } ) ↔ ( ℩ 𝑦 ∈ { 𝑥 ∈ No ∣ ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) } ( bday ‘ 𝑦 ) = ∩ ( bday “ { 𝑥 ∈ No ∣ ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) } ) ) = ( 𝐴 |s 𝐵 ) ) )
15 11 12 14 syl2anc ⊢ ( 𝐴 <<s 𝐵 → ( ( bday ‘ ( 𝐴 |s 𝐵 ) ) = ∩ ( bday “ { 𝑥 ∈ No ∣ ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) } ) ↔ ( ℩ 𝑦 ∈ { 𝑥 ∈ No ∣ ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) } ( bday ‘ 𝑦 ) = ∩ ( bday “ { 𝑥 ∈ No ∣ ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) } ) ) = ( 𝐴 |s 𝐵 ) ) )
16 2 15 mpbird ⊢ ( 𝐴 <<s 𝐵 → ( bday ‘ ( 𝐴 |s 𝐵 ) ) = ∩ ( bday “ { 𝑥 ∈ No ∣ ( 𝐴 <<s { 𝑥 } ∧ { 𝑥 } <<s 𝐵 ) } ) )