Metamath Proof Explorer


Definition df-abss

Description: Define the surreal absolute value function. See abssval for its value and absscl for its closure. (Contributed by Scott Fenton, 16-Apr-2025)

Ref Expression
Assertion df-abss abss = ( 𝑥 ∈ No ↦ if ( 0s ≤s 𝑥 , 𝑥 , ( -us ‘ 𝑥 ) ) )

Detailed syntax breakdown

Step Hyp Ref Expression
0 cabss ⊢ abss
1 vx ⊢ 𝑥
2 csur ⊢ No
3 c0s ⊢ 0s
4 cles ⊢ ≤s
5 1 cv ⊢ 𝑥
6 3 5 4 wbr ⊢ 0s ≤s 𝑥
7 cnegs ⊢ -us
8 5 7 cfv ⊢ ( -us ‘ 𝑥 )
9 6 5 8 cif ⊢ if ( 0s ≤s 𝑥 , 𝑥 , ( -us ‘ 𝑥 ) )
10 1 2 9 cmpt ⊢ ( 𝑥 ∈ No ↦ if ( 0s ≤s 𝑥 , 𝑥 , ( -us ‘ 𝑥 ) ) )
11 0 10 wceq ⊢ abss = ( 𝑥 ∈ No ↦ if ( 0s ≤s 𝑥 , 𝑥 , ( -us ‘ 𝑥 ) ) )