Metamath Proof Explorer


Definition df-coss

Description: Define the class of cosets by R : x and y are cosets by R iff there exists a set u such that both u R x and u R y hold, i.e., both x and y are are elements of the R -coset of u (see dfcoss2 and the comment of dfec2 ). R is usually a relation.

This concept simplifies theorems relating partition and equivalence: the left side of these theorems relate to R , the right side relate to ,R (see e.g. pet ). Without the definition of ,R we should have to relate the right side of these theorems to a composition of a converse (cf. dfcoss3 ) or to the range of a range Cartesian product of classes (cf. dfcoss4 ), which would make the theorems complicated and confusing. Alternate definition is dfcoss2 . Technically, we can define it via composition ( dfcoss3 ) or as the range of a range Cartesian product ( dfcoss4 ), but neither of these definitions reveal directly how the cosets by R relate to each other. We define functions ( df-funsALTV , df-funALTV ) and disjoints ( dfdisjs , dfdisjs2 , df-disjALTV , dfdisjALTV2 ) with the help of it as well. (Contributed by Peter Mazsa, 9-Jan-2018)

Ref Expression
Assertion df-coss ≀ 𝑅 = { ⟨ 𝑥 , 𝑦 ⟩ ∣ ∃ 𝑢 ( 𝑢 𝑅 𝑥 ∧ 𝑢 𝑅 𝑦 ) }

Detailed syntax breakdown

Step Hyp Ref Expression
0 cR ⊢ 𝑅
1 0 ccoss ⊢ ≀ 𝑅
2 vx ⊢ 𝑥
3 vy ⊢ 𝑦
4 vu ⊢ 𝑢
5 4 cv ⊢ 𝑢
6 2 cv ⊢ 𝑥
7 5 6 0 wbr ⊢ 𝑢 𝑅 𝑥
8 3 cv ⊢ 𝑦
9 5 8 0 wbr ⊢ 𝑢 𝑅 𝑦
10 7 9 wa ⊢ ( 𝑢 𝑅 𝑥 ∧ 𝑢 𝑅 𝑦 )
11 10 4 wex ⊢ ∃ 𝑢 ( 𝑢 𝑅 𝑥 ∧ 𝑢 𝑅 𝑦 )
12 11 2 3 copab ⊢ { ⟨ 𝑥 , 𝑦 ⟩ ∣ ∃ 𝑢 ( 𝑢 𝑅 𝑥 ∧ 𝑢 𝑅 𝑦 ) }
13 1 12 wceq ⊢ ≀ 𝑅 = { ⟨ 𝑥 , 𝑦 ⟩ ∣ ∃ 𝑢 ( 𝑢 𝑅 𝑥 ∧ 𝑢 𝑅 𝑦 ) }