Metamath Proof Explorer


Definition df-eldisj

Description: Define the disjoint elementhood relation predicate, i.e., the disjoint elementhood predicate. Read: the elements of A are disjoint. The element of the disjoint elements class and the disjoint elementhood predicate are the same, that is ( A e. ElDisjs <-> ElDisj A ) when A is a set, see eleldisjseldisj .

As of now, disjoint elementhood is defined as "partition" in set.mm : compare df-prt with dfeldisj5 . See also the comments of ~? dfmembpart2 and of ~? df-parts . (Contributed by Peter Mazsa, 17-Jul-2021)

Ref Expression
Assertion df-eldisj ( ElDisj 𝐴 ↔ Disj ( E ↾ 𝐴 ) )

Detailed syntax breakdown

Step Hyp Ref Expression
0 cA 𝐴
1 0 weldisj ElDisj 𝐴
2 cep E
3 2 ccnv E
4 3 0 cres ( E ↾ 𝐴 )
5 4 wdisjALTV Disj ( E ↾ 𝐴 )
6 1 5 wb ( ElDisj 𝐴 ↔ Disj ( E ↾ 𝐴 ) )