Metamath Proof Explorer


Definition df-resub

Description: Define subtraction between real numbers. This operator saves a few axioms over df-sub in certain situations. Theorem resubval shows its value, resubadd relates it to addition, and rersubcl proves its closure. It is the restriction of df-sub to the reals: subresre . (Contributed by Steven Nguyen, 7-Jan-2023)

Ref Expression
Assertion df-resub −ℝ = ( 𝑥 ∈ ℝ , 𝑦 ∈ ℝ ↦ ( ℩ 𝑧 ∈ ℝ ( 𝑦 + 𝑧 ) = 𝑥 ) )

Detailed syntax breakdown

Step Hyp Ref Expression
0 cresub ⊢ −ℝ
1 vx ⊢ 𝑥
2 cr ⊢ ℝ
3 vy ⊢ 𝑦
4 vz ⊢ 𝑧
5 3 cv ⊢ 𝑦
6 caddc ⊢ +
7 4 cv ⊢ 𝑧
8 5 7 6 co ⊢ ( 𝑦 + 𝑧 )
9 1 cv ⊢ 𝑥
10 8 9 wceq ⊢ ( 𝑦 + 𝑧 ) = 𝑥
11 10 4 2 crio ⊢ ( ℩ 𝑧 ∈ ℝ ( 𝑦 + 𝑧 ) = 𝑥 )
12 1 3 2 2 11 cmpo ⊢ ( 𝑥 ∈ ℝ , 𝑦 ∈ ℝ ↦ ( ℩ 𝑧 ∈ ℝ ( 𝑦 + 𝑧 ) = 𝑥 ) )
13 0 12 wceq ⊢ −ℝ = ( 𝑥 ∈ ℝ , 𝑦 ∈ ℝ ↦ ( ℩ 𝑧 ∈ ℝ ( 𝑦 + 𝑧 ) = 𝑥 ) )