Metamath Proof Explorer


Theorem df3nandALT2

Description: The double nand expressed in terms of negation and and not. (Contributed by Anthony Hart, 13-Sep-2011)

Ref Expression
Assertion df3nandALT2 ( ( 𝜑 ⊼ 𝜓 ⊼ 𝜒 ) ↔ ¬ ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) )

Proof

Step Hyp Ref Expression
1 df-3nand ⊢ ( ( 𝜑 ⊼ 𝜓 ⊼ 𝜒 ) ↔ ( 𝜑 → ( 𝜓 → ¬ 𝜒 ) ) )
2 imnan ⊢ ( ( 𝜓 → ¬ 𝜒 ) ↔ ¬ ( 𝜓 ∧ 𝜒 ) )
3 2 imbi2i ⊢ ( ( 𝜑 → ( 𝜓 → ¬ 𝜒 ) ) ↔ ( 𝜑 → ¬ ( 𝜓 ∧ 𝜒 ) ) )
4 imnan ⊢ ( ( 𝜑 → ¬ ( 𝜓 ∧ 𝜒 ) ) ↔ ¬ ( 𝜑 ∧ ( 𝜓 ∧ 𝜒 ) ) )
5 3anass ⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) ↔ ( 𝜑 ∧ ( 𝜓 ∧ 𝜒 ) ) )
6 4 5 xchbinxr ⊢ ( ( 𝜑 → ¬ ( 𝜓 ∧ 𝜒 ) ) ↔ ¬ ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) )
7 1 3 6 3bitri ⊢ ( ( 𝜑 ⊼ 𝜓 ⊼ 𝜒 ) ↔ ¬ ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) )