Metamath Proof Explorer


Theorem dfacycgr1

Description: An alternate definition of the class of all acyclic graphs that requires all cycles to be trivial. (Contributed by BTernaryTau, 11-Oct-2023)

Ref Expression
Assertion dfacycgr1 AcyclicGraph = { 𝑔 ∣ ∀ 𝑓 ∀ 𝑝 ( 𝑓 ( Cycles ‘ 𝑔 ) 𝑝 → 𝑓 = ∅ ) }

Proof

Step Hyp Ref Expression
1 df-acycgr ⊢ AcyclicGraph = { 𝑔 ∣ ¬ ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝑔 ) 𝑝 ∧ 𝑓 ≠ ∅ ) }
2 2exanali ⊢ ( ¬ ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝑔 ) 𝑝 ∧ ¬ 𝑓 = ∅ ) ↔ ∀ 𝑓 ∀ 𝑝 ( 𝑓 ( Cycles ‘ 𝑔 ) 𝑝 → 𝑓 = ∅ ) )
3 df-ne ⊢ ( 𝑓 ≠ ∅ ↔ ¬ 𝑓 = ∅ )
4 3 anbi2i ⊢ ( ( 𝑓 ( Cycles ‘ 𝑔 ) 𝑝 ∧ 𝑓 ≠ ∅ ) ↔ ( 𝑓 ( Cycles ‘ 𝑔 ) 𝑝 ∧ ¬ 𝑓 = ∅ ) )
5 4 2exbii ⊢ ( ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝑔 ) 𝑝 ∧ 𝑓 ≠ ∅ ) ↔ ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝑔 ) 𝑝 ∧ ¬ 𝑓 = ∅ ) )
6 2 5 xchnxbir ⊢ ( ¬ ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝑔 ) 𝑝 ∧ 𝑓 ≠ ∅ ) ↔ ∀ 𝑓 ∀ 𝑝 ( 𝑓 ( Cycles ‘ 𝑔 ) 𝑝 → 𝑓 = ∅ ) )
7 6 abbii ⊢ { 𝑔 ∣ ¬ ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝑔 ) 𝑝 ∧ 𝑓 ≠ ∅ ) } = { 𝑔 ∣ ∀ 𝑓 ∀ 𝑝 ( 𝑓 ( Cycles ‘ 𝑔 ) 𝑝 → 𝑓 = ∅ ) }
8 1 7 eqtri ⊢ AcyclicGraph = { 𝑔 ∣ ∀ 𝑓 ∀ 𝑝 ( 𝑓 ( Cycles ‘ 𝑔 ) 𝑝 → 𝑓 = ∅ ) }