Metamath Proof Explorer


Theorem isacycgr

Description: The property of being an acyclic graph. (Contributed by BTernaryTau, 11-Oct-2023)

Ref Expression
Assertion isacycgr ( 𝐺 ∈ 𝑊 → ( 𝐺 ∈ AcyclicGraph ↔ ¬ ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝐺 ) 𝑝 ∧ 𝑓 ≠ ∅ ) ) )

Proof

Step Hyp Ref Expression
1 fveq2 ⊢ ( 𝑔 = 𝐺 → ( Cycles ‘ 𝑔 ) = ( Cycles ‘ 𝐺 ) )
2 1 breqd ⊢ ( 𝑔 = 𝐺 → ( 𝑓 ( Cycles ‘ 𝑔 ) 𝑝 ↔ 𝑓 ( Cycles ‘ 𝐺 ) 𝑝 ) )
3 2 anbi1d ⊢ ( 𝑔 = 𝐺 → ( ( 𝑓 ( Cycles ‘ 𝑔 ) 𝑝 ∧ 𝑓 ≠ ∅ ) ↔ ( 𝑓 ( Cycles ‘ 𝐺 ) 𝑝 ∧ 𝑓 ≠ ∅ ) ) )
4 3 2exbidv ⊢ ( 𝑔 = 𝐺 → ( ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝑔 ) 𝑝 ∧ 𝑓 ≠ ∅ ) ↔ ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝐺 ) 𝑝 ∧ 𝑓 ≠ ∅ ) ) )
5 4 notbid ⊢ ( 𝑔 = 𝐺 → ( ¬ ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝑔 ) 𝑝 ∧ 𝑓 ≠ ∅ ) ↔ ¬ ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝐺 ) 𝑝 ∧ 𝑓 ≠ ∅ ) ) )
6 df-acycgr ⊢ AcyclicGraph = { 𝑔 ∣ ¬ ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝑔 ) 𝑝 ∧ 𝑓 ≠ ∅ ) }
7 5 6 elab2g ⊢ ( 𝐺 ∈ 𝑊 → ( 𝐺 ∈ AcyclicGraph ↔ ¬ ∃ 𝑓 ∃ 𝑝 ( 𝑓 ( Cycles ‘ 𝐺 ) 𝑝 ∧ 𝑓 ≠ ∅ ) ) )