Metamath Proof Explorer


Theorem dfcomember2

Description: Alternate definition of the comember equivalence relation. (Contributed by Peter Mazsa, 25-Sep-2021)

Ref Expression
Assertion dfcomember2 ( CoMembEr 𝐴 ↔ ( EqvRel ∼ 𝐴 ∧ ( dom ∼ 𝐴 /𝐴 ) = 𝐴 ) )

Proof

Step Hyp Ref Expression
1 dfcomember ( CoMembEr 𝐴 ↔ ∼ 𝐴 ErALTV 𝐴 )
2 dferALTV2 ( ∼ 𝐴 ErALTV 𝐴 ↔ ( EqvRel ∼ 𝐴 ∧ ( dom ∼ 𝐴 /𝐴 ) = 𝐴 ) )
3 1 2 bitri ( CoMembEr 𝐴 ↔ ( EqvRel ∼ 𝐴 ∧ ( dom ∼ 𝐴 /𝐴 ) = 𝐴 ) )