Metamath Proof Explorer


Theorem dfcomember3

Description: Alternate definition of the comember equivalence relation. (Contributed by Peter Mazsa, 26-Sep-2021) (Revised by Peter Mazsa, 17-Jul-2023)

Ref Expression
Assertion dfcomember3 ( CoMembEr 𝐴 ↔ ( CoElEqvRel 𝐴 ∧ ( ∪ 𝐴 / ∼ 𝐴 ) = 𝐴 ) )

Proof

Step Hyp Ref Expression
1 dfcomember2 ⊢ ( CoMembEr 𝐴 ↔ ( EqvRel ∼ 𝐴 ∧ ( dom ∼ 𝐴 / ∼ 𝐴 ) = 𝐴 ) )
2 dfcoeleqvrel ⊢ ( CoElEqvRel 𝐴 ↔ EqvRel ∼ 𝐴 )
3 2 bicomi ⊢ ( EqvRel ∼ 𝐴 ↔ CoElEqvRel 𝐴 )
4 dmqscoelseq ⊢ ( ( dom ∼ 𝐴 / ∼ 𝐴 ) = 𝐴 ↔ ( ∪ 𝐴 / ∼ 𝐴 ) = 𝐴 )
5 3 4 anbi12i ⊢ ( ( EqvRel ∼ 𝐴 ∧ ( dom ∼ 𝐴 / ∼ 𝐴 ) = 𝐴 ) ↔ ( CoElEqvRel 𝐴 ∧ ( ∪ 𝐴 / ∼ 𝐴 ) = 𝐴 ) )
6 1 5 bitri ⊢ ( CoMembEr 𝐴 ↔ ( CoElEqvRel 𝐴 ∧ ( ∪ 𝐴 / ∼ 𝐴 ) = 𝐴 ) )