Metamath Proof Explorer


Theorem eqvreldmqs

Description: Two ways to express comember equivalence relation on its domain quotient. (Contributed by Peter Mazsa, 26-Sep-2021) (Revised by Peter Mazsa, 17-Jul-2023)

Ref Expression
Assertion eqvreldmqs ( ( EqvRel ≀ ( ◡ E ↾ 𝐴 ) ∧ ( dom ≀ ( ◡ E ↾ 𝐴 ) / ≀ ( ◡ E ↾ 𝐴 ) ) = 𝐴 ) ↔ ( CoElEqvRel 𝐴 ∧ ( ∪ 𝐴 / ∼ 𝐴 ) = 𝐴 ) )

Proof

Step Hyp Ref Expression
1 df-coeleqvrel ⊢ ( CoElEqvRel 𝐴 ↔ EqvRel ≀ ( ◡ E ↾ 𝐴 ) )
2 1 bicomi ⊢ ( EqvRel ≀ ( ◡ E ↾ 𝐴 ) ↔ CoElEqvRel 𝐴 )
3 dmqs1cosscnvepreseq ⊢ ( ( dom ≀ ( ◡ E ↾ 𝐴 ) / ≀ ( ◡ E ↾ 𝐴 ) ) = 𝐴 ↔ ( ∪ 𝐴 / ∼ 𝐴 ) = 𝐴 )
4 2 3 anbi12i ⊢ ( ( EqvRel ≀ ( ◡ E ↾ 𝐴 ) ∧ ( dom ≀ ( ◡ E ↾ 𝐴 ) / ≀ ( ◡ E ↾ 𝐴 ) ) = 𝐴 ) ↔ ( CoElEqvRel 𝐴 ∧ ( ∪ 𝐴 / ∼ 𝐴 ) = 𝐴 ) )