Metamath Proof Explorer


Theorem dfralseu2

Description: The bounded "all some one" form is the general form with the class membership folded into the antecedent. This is the "all some one" counterpart of dfrals2 . (Contributed by David A. Wheeler, 21-Jul-2026)

Ref Expression
Assertion dfralseu2 ( ∀∃! 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ↔ ∀∃! 𝑥 ( ( 𝑥 ∈ 𝐴 ∧ 𝜑 ) → 𝜓 ) )

Proof

Step Hyp Ref Expression
1 df-ral ⊢ ( ∀ 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ↔ ∀ 𝑥 ( 𝑥 ∈ 𝐴 → ( 𝜑 → 𝜓 ) ) )
2 impexp ⊢ ( ( ( 𝑥 ∈ 𝐴 ∧ 𝜑 ) → 𝜓 ) ↔ ( 𝑥 ∈ 𝐴 → ( 𝜑 → 𝜓 ) ) )
3 2 albii ⊢ ( ∀ 𝑥 ( ( 𝑥 ∈ 𝐴 ∧ 𝜑 ) → 𝜓 ) ↔ ∀ 𝑥 ( 𝑥 ∈ 𝐴 → ( 𝜑 → 𝜓 ) ) )
4 1 3 bitr4i ⊢ ( ∀ 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ↔ ∀ 𝑥 ( ( 𝑥 ∈ 𝐴 ∧ 𝜑 ) → 𝜓 ) )
5 df-reu ⊢ ( ∃! 𝑥 ∈ 𝐴 𝜑 ↔ ∃! 𝑥 ( 𝑥 ∈ 𝐴 ∧ 𝜑 ) )
6 4 5 anbi12i ⊢ ( ( ∀ 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ∧ ∃! 𝑥 ∈ 𝐴 𝜑 ) ↔ ( ∀ 𝑥 ( ( 𝑥 ∈ 𝐴 ∧ 𝜑 ) → 𝜓 ) ∧ ∃! 𝑥 ( 𝑥 ∈ 𝐴 ∧ 𝜑 ) ) )
7 df-ralseu ⊢ ( ∀∃! 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ↔ ( ∀ 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ∧ ∃! 𝑥 ∈ 𝐴 𝜑 ) )
8 df-alseu ⊢ ( ∀∃! 𝑥 ( ( 𝑥 ∈ 𝐴 ∧ 𝜑 ) → 𝜓 ) ↔ ( ∀ 𝑥 ( ( 𝑥 ∈ 𝐴 ∧ 𝜑 ) → 𝜓 ) ∧ ∃! 𝑥 ( 𝑥 ∈ 𝐴 ∧ 𝜑 ) ) )
9 6 7 8 3bitr4i ⊢ ( ∀∃! 𝑥 ∈ 𝐴 ( 𝜑 → 𝜓 ) ↔ ∀∃! 𝑥 ( ( 𝑥 ∈ 𝐴 ∧ 𝜑 ) → 𝜓 ) )