Metamath Proof Explorer


Theorem elcnvcnvlem

Description: Two ways to say a set is a member of the converse of the converse of a class. (Contributed by RP, 20-Aug-2020)

Ref Expression
Assertion elcnvcnvlem ( 𝐴 ∈ ◡ ◡ 𝐵 ↔ ( 𝐴 ∈ ( V × V ) ∧ ( I ‘ 𝐴 ) ∈ 𝐵 ) )

Proof

Step Hyp Ref Expression
1 cnvcnv ⊢ ◡ ◡ 𝐵 = ( 𝐵 ∩ ( V × V ) )
2 incom ⊢ ( 𝐵 ∩ ( V × V ) ) = ( ( V × V ) ∩ 𝐵 )
3 1 2 eqtri ⊢ ◡ ◡ 𝐵 = ( ( V × V ) ∩ 𝐵 )
4 3 eleq2i ⊢ ( 𝐴 ∈ ◡ ◡ 𝐵 ↔ 𝐴 ∈ ( ( V × V ) ∩ 𝐵 ) )
5 elinlem ⊢ ( 𝐴 ∈ ( ( V × V ) ∩ 𝐵 ) ↔ ( 𝐴 ∈ ( V × V ) ∧ ( I ‘ 𝐴 ) ∈ 𝐵 ) )
6 4 5 bitri ⊢ ( 𝐴 ∈ ◡ ◡ 𝐵 ↔ ( 𝐴 ∈ ( V × V ) ∧ ( I ‘ 𝐴 ) ∈ 𝐵 ) )