Metamath Proof Explorer


Theorem eldisjim2

Description: Alternate form of eldisjim . (Contributed by Peter Mazsa, 30-Dec-2024)

Ref Expression
Assertion eldisjim2 ( ElDisj 𝐴 → EqvRel ∼ 𝐴 )

Proof

Step Hyp Ref Expression
1 disjim ⊢ ( Disj ( ◡ E ↾ 𝐴 ) → EqvRel ≀ ( ◡ E ↾ 𝐴 ) )
2 df-eldisj ⊢ ( ElDisj 𝐴 ↔ Disj ( ◡ E ↾ 𝐴 ) )
3 df-coels ⊢ ∼ 𝐴 = ≀ ( ◡ E ↾ 𝐴 )
4 3 eqvreleqi ⊢ ( EqvRel ∼ 𝐴 ↔ EqvRel ≀ ( ◡ E ↾ 𝐴 ) )
5 1 2 4 3imtr4i ⊢ ( ElDisj 𝐴 → EqvRel ∼ 𝐴 )