Metamath Proof Explorer


Theorem eleqtrd

Description: Deduction that substitutes equal classes into membership. (Contributed by NM, 14-Dec-2004)

Ref Expression
Hypotheses eleqtrd.1 ⊢ ( 𝜑 → 𝐴 ∈ 𝐵 )
eleqtrd.2 ⊢ ( 𝜑 → 𝐵 = 𝐶 )
Assertion eleqtrd ( 𝜑 → 𝐴 ∈ 𝐶 )

Proof

Step Hyp Ref Expression
1 eleqtrd.1 ⊢ ( 𝜑 → 𝐴 ∈ 𝐵 )
2 eleqtrd.2 ⊢ ( 𝜑 → 𝐵 = 𝐶 )
3 2 eleq2d ⊢ ( 𝜑 → ( 𝐴 ∈ 𝐵 ↔ 𝐴 ∈ 𝐶 ) )
4 1 3 mpbid ⊢ ( 𝜑 → 𝐴 ∈ 𝐶 )