Metamath Proof Explorer


Theorem elpssex

Description: A class has an element just in case it has a proper subset. (Contributed by Adrian Ducourtial, 26-Oct-2026)

Ref Expression
Assertion elpssex ( ∃ 𝑥 𝑥 ∈ 𝐴 ↔ ∃ 𝑦 𝑦 ⊊ 𝐴 )

Proof

Step Hyp Ref Expression
1 0ss ⊢ ∅ ⊆ 𝐴
2 1 a1i ⊢ ( 𝑥 ∈ 𝐴 → ∅ ⊆ 𝐴 )
3 ne0i ⊢ ( 𝑥 ∈ 𝐴 → 𝐴 ≠ ∅ )
4 3 necomd ⊢ ( 𝑥 ∈ 𝐴 → ∅ ≠ 𝐴 )
5 df-pss ⊢ ( ∅ ⊊ 𝐴 ↔ ( ∅ ⊆ 𝐴 ∧ ∅ ≠ 𝐴 ) )
6 2 4 5 sylanbrc ⊢ ( 𝑥 ∈ 𝐴 → ∅ ⊊ 𝐴 )
7 0ex ⊢ ∅ ∈ V
8 psseq1 ⊢ ( 𝑦 = ∅ → ( 𝑦 ⊊ 𝐴 ↔ ∅ ⊊ 𝐴 ) )
9 7 8 spcev ⊢ ( ∅ ⊊ 𝐴 → ∃ 𝑦 𝑦 ⊊ 𝐴 )
10 6 9 syl ⊢ ( 𝑥 ∈ 𝐴 → ∃ 𝑦 𝑦 ⊊ 𝐴 )
11 10 exlimiv ⊢ ( ∃ 𝑥 𝑥 ∈ 𝐴 → ∃ 𝑦 𝑦 ⊊ 𝐴 )
12 pssnel ⊢ ( 𝑦 ⊊ 𝐴 → ∃ 𝑥 ( 𝑥 ∈ 𝐴 ∧ ¬ 𝑥 ∈ 𝑦 ) )
13 exsimpl ⊢ ( ∃ 𝑥 ( 𝑥 ∈ 𝐴 ∧ ¬ 𝑥 ∈ 𝑦 ) → ∃ 𝑥 𝑥 ∈ 𝐴 )
14 12 13 syl ⊢ ( 𝑦 ⊊ 𝐴 → ∃ 𝑥 𝑥 ∈ 𝐴 )
15 14 exlimiv ⊢ ( ∃ 𝑦 𝑦 ⊊ 𝐴 → ∃ 𝑥 𝑥 ∈ 𝐴 )
16 11 15 impbii ⊢ ( ∃ 𝑥 𝑥 ∈ 𝐴 ↔ ∃ 𝑦 𝑦 ⊊ 𝐴 )