Metamath Proof Explorer


Theorem pssnel

Description: A proper subclass has a member in one argument that's not in both. (Contributed by NM, 29-Feb-1996)

Ref Expression
Assertion pssnel ( 𝐴 ⊊ 𝐵 → ∃ 𝑥 ( 𝑥 ∈ 𝐵 ∧ ¬ 𝑥 ∈ 𝐴 ) )

Proof

Step Hyp Ref Expression
1 pssdif ⊢ ( 𝐴 ⊊ 𝐵 → ( 𝐵 ∖ 𝐴 ) ≠ ∅ )
2 n0 ⊢ ( ( 𝐵 ∖ 𝐴 ) ≠ ∅ ↔ ∃ 𝑥 𝑥 ∈ ( 𝐵 ∖ 𝐴 ) )
3 1 2 sylib ⊢ ( 𝐴 ⊊ 𝐵 → ∃ 𝑥 𝑥 ∈ ( 𝐵 ∖ 𝐴 ) )
4 eldif ⊢ ( 𝑥 ∈ ( 𝐵 ∖ 𝐴 ) ↔ ( 𝑥 ∈ 𝐵 ∧ ¬ 𝑥 ∈ 𝐴 ) )
5 4 exbii ⊢ ( ∃ 𝑥 𝑥 ∈ ( 𝐵 ∖ 𝐴 ) ↔ ∃ 𝑥 ( 𝑥 ∈ 𝐵 ∧ ¬ 𝑥 ∈ 𝐴 ) )
6 3 5 sylib ⊢ ( 𝐴 ⊊ 𝐵 → ∃ 𝑥 ( 𝑥 ∈ 𝐵 ∧ ¬ 𝑥 ∈ 𝐴 ) )