Metamath Proof Explorer


Theorem fdmrn

Description: A different way to write F is a function. (Contributed by Thierry Arnoux, 7-Dec-2016)

Ref Expression
Assertion fdmrn ( Fun 𝐹𝐹 : dom 𝐹 ⟶ ran 𝐹 )

Proof

Step Hyp Ref Expression
1 ssid ran 𝐹 ⊆ ran 𝐹
2 df-f ( 𝐹 : dom 𝐹 ⟶ ran 𝐹 ↔ ( 𝐹 Fn dom 𝐹 ∧ ran 𝐹 ⊆ ran 𝐹 ) )
3 1 2 mpbiran2 ( 𝐹 : dom 𝐹 ⟶ ran 𝐹𝐹 Fn dom 𝐹 )
4 eqid dom 𝐹 = dom 𝐹
5 df-fn ( 𝐹 Fn dom 𝐹 ↔ ( Fun 𝐹 ∧ dom 𝐹 = dom 𝐹 ) )
6 4 5 mpbiran2 ( 𝐹 Fn dom 𝐹 ↔ Fun 𝐹 )
7 3 6 bitr2i ( Fun 𝐹𝐹 : dom 𝐹 ⟶ ran 𝐹 )