Metamath Proof Explorer


Theorem fnimadisj

Description: A class that is disjoint with the domain of a function has an empty image under the function. (Contributed by FL, 24-Jan-2007)

Ref Expression
Assertion fnimadisj ( ( 𝐹 Fn 𝐴 ∧ ( 𝐴𝐶 ) = ∅ ) → ( 𝐹𝐶 ) = ∅ )

Proof

Step Hyp Ref Expression
1 fndm ( 𝐹 Fn 𝐴 → dom 𝐹 = 𝐴 )
2 1 ineq1d ( 𝐹 Fn 𝐴 → ( dom 𝐹𝐶 ) = ( 𝐴𝐶 ) )
3 2 eqeq1d ( 𝐹 Fn 𝐴 → ( ( dom 𝐹𝐶 ) = ∅ ↔ ( 𝐴𝐶 ) = ∅ ) )
4 3 biimpar ( ( 𝐹 Fn 𝐴 ∧ ( 𝐴𝐶 ) = ∅ ) → ( dom 𝐹𝐶 ) = ∅ )
5 imadisj ( ( 𝐹𝐶 ) = ∅ ↔ ( dom 𝐹𝐶 ) = ∅ )
6 4 5 sylibr ( ( 𝐹 Fn 𝐴 ∧ ( 𝐴𝐶 ) = ∅ ) → ( 𝐹𝐶 ) = ∅ )